tolong kerjaka pakai cara yach!! makasih

4) (2 / x√x) dx
= (2 / x^3/2) dx
= (2x^-3/2) dx
baru integral kan
= (2/(-3/2+1))x^(-3/2+1)
= (2/-½)x^-½
= -4x^-½
= -4/√x
baru masukan interval 4 dan 1
= (-4/√4) - (-4/√1)
= (-4/2) - (-4/1)
= -2 - (-4)
= -2 + 4
= 2

5) 12x(x²+1)² dx
= 12x(u)² du/2x
= (12x/2x)u² du
= 6u² du
integral kan
= 2u³
= 2(x² + 1)³
masukan interval 1 dan 0
= {2(1² + 1)³} - {2(0² + 1)³}
= {2(2)³} - {2(1)³}
= {2(8)} - {2(1)}
= 16 - 2
= 14