diketahui barisan arimatika -8-4,0,4,.....384 berapakah nilai suku tengah

Langsung aja.. Suku tengah = (suku pertama + suku terakhir)/2

(-8+384)/2
376/2
188

Jawabnya 188

Barisan Aritmatika
a = –8

b = U2 –U1
b = –4 – (–8)
b = 4

Un = a + (n–1)b

384 = –8 + (n–1)4
384 = –8 + 4n – 4
384 = 4n – 12
4n = 384 + 12
4n = 396
n = 396/4
n = 99

Suku tengah
= (99+1) / 2
= 50

U50 = a + 49b
U50 = –8 + (49×4)
U50 = –8 + 196
U50 = 188