Jika 3/x+5 - x-4/x kuadrat + x-20 = ax-4a/(x+b)(x-c)maka perbandingan (b-c):a =

3/x+5 - x-4/x²+x-20 = ax-4a/(x+b)(x-c)

3/(x+5) - (x-4)/(x+5)(x-4)

Kita samakan penyebutnya menjadi (x+5)(x-4)

Maka ;

3(x-4)/(x+5)(x-4) - (x-4)/(x+5)(x-4)
<=> 2(x-4) / (x+5)(x-4)

<=> 2x-8 / (x+5)(x-4)

Jadi;

ax - 4a = 2x - 8

a = 2

b = 5

c = 4

Maka (b-c ) : a = 1 : 2