Kak tolong di bantu y pakai jalan bsk mau dikumpul ku ksih poin banyak deh

Bab Fungsi

f(x) = 2x^2 - 5 x + 3

x = {0,1,2,3}

f(0) = 2(0)^2 - 5(0) + 3 = 0 - 0 + 3 = 3

f(1) = 2(1)^2 - 5(1) + 3 = 2 - 5 + 3 = 0

f(2) = 2 (2)^2 - 5(2) + 3 = 2(4) - 10 + 3
=8 - 10 + 3
= -2 + 3
= 1

f(3) = 2(3)^2 - 5(3) + 3 = 2(9) - 15 + 3
=18 - 12
= 6

Daerah Hasil = {3,0,1,6}

Tidak Ada Opsi

11. f(x)=2x²-5x+3
x={0,1,2,3}
jawaban:
a. x=0
2x²-5x+3=2(0)²-5(0)+3
= 0-0+3
=3
b. x=1
2x²-5x+3=2(1)²-5(1)+3
=4-5+3
=0
c. x=2
2x²-5x+3=2(2)²-5(2)+3
=8-10+3
=1
d. x=3
2x²-5x+3=2(3)²-5(3)+3
=18-15+3
=6
jadi daerah hasil fungsi {3,0,1,6}
tidak ada opsi pilihan jawaban

semoga membantu maaf kalau salah