pada gambar diatas, diketahui panjang PR= 12cm dan PS= 6 cm. Hitunglah: a. panjang PQ b. panjang RS tolong yaa makasi

PR = 12 cm
PS = 6 cm

a] PQ
b] RS

a]
(PR)^2 = PS × PQ
12^2 = 6 × (SQ + 6)
144 = 6SQ + 36
6SQ = 144 - 36
6SQ = 108
SQ = 108/6
SQ = 18 cm

PQ = PS + SQ
PQ = 6 + 18
PQ = 24 cm

b]
(RS)^2 = (PR)^2 - (PS)^2
(RS)^2 = 12^2 - 6^2
(RS)^2 = 144 - 36
(RS)^2 = 108
RS = V108
RS = V(36×3)
RS = V36V3
RS = 6V3 cm
RS = 10,39 cm