Soal Berupa Lampiran yah Kak -> Pakai Cara Makasih...

Penyelesaian:

Ingat: a^m . a^n = a^m+n
a^m / a^n = a^m-n
a^1/2 = √a
a^1/3 = [tex] \sqrt[3]{a} [/tex]

7. [tex] \frac{x^3 . y^6}{x^4 . y^-3} . \frac{x . y^-4}{x^7 . y} [/tex]
= x^(3+1-4-7) . y^(6-4+3-1)
= [tex]x^-7 . y^4[/tex]  (B).

8. [tex] \sqrt{ \frac{4}{9} } + \sqrt[3]{ \frac{8}{27} } + \sqrt[4]{ \frac{16}{81} } [/tex]
= [tex] \frac{2}{3} + \frac{2}{3} + \frac{2}{3} [/tex]
= 2  (C).

Bentuk Eksponen
Matematika IX

[7].
[tex] \frac{x^{3}.y^{6}}{x^{4}.y^{-3}}: \frac{x^{7}.y}{x.y^{-4}} [/tex]
[tex]=[ \frac{x^{3}.y^{6}}{x^{4}.y^{-3}}].[ \frac{x.y^{-4}}{x^{7}.y}] [/tex]
[tex]=[x^{3-4}.y^{6+3}].[x^{1-7}.y^{-4-1}] [/tex]
[tex]=[x^{-1}.y^{9}].[x^{-6}.y^{-5}] [/tex]
[tex]=x^{-1-6}.y^{9-5} [/tex]
[tex]=x^{-7}.y^{4}[/tex]

[8].
[tex][ \frac{4}{9} ]^{ \frac{1}{2}} + [ \frac{8}{27} ]^{ \frac{1}{3}} + [ \frac{16}{81} ]^{ \frac{1}{4}} [/tex]
[tex]=[ \frac{2^{2}}{3^{2}} ]^{ \frac{1}{2}} + [ \frac{2^{3}}{3^{3}} ]^{ \frac{1}{3}} + [ \frac{2^{4}}{3^{4}} ]^{ \frac{1}{4}} [/tex]
[tex]=[ (\frac{2}{3})^{2} ]^{ \frac{1}{2}} + [ (\frac{2}{3})^{3} ]^{ \frac{1}{3}} + [ (\frac{2}{3})^{4} ]^{ \frac{1}{4}}[/tex]
[tex]= (\frac{2}{3})^{2}^{.}^{ \frac{1}{2}} + (\frac{2}{3})^{3}^{.}^{ \frac{1}{3}} + (\frac{2}{3})^{4} ^{.}^{ \frac{1}{4}}[/tex]
[tex]=\frac{2}{3}+\frac{2}{3}+\frac{2}{3} [/tex]
[tex]= \frac{6}{3} [/tex]
[tex]=2[/tex]