Tolong dibantu no 2 memcari resultan F nya aja pakai cara yg lengkap.dan jawaban yg benar

Diket :
Gambar tiga vektor,
# F1 = 40 N
Dng arah, θ = 30° thd Sumbu Y positif
F1x = F1.sin θ
F1x = 40• sin 30°
F1x = 40•1/2
F1x = 20 N
Dan
F1y = F1.cos θ
F1y = 40•cos 30°
F1y = 40• 1/2√3
F1y = 20√3 N

# F2 = 20 N
Dng arah, θ = 60° thd Sumbu x negatif
F2x = - F2.cos θ
F2x = - 20•cos 60°
F2x = - 20•1/2
F2x = - 10 N
Dan
F2y = - F2.sin θ
F2y = - 20• sin 60°
F2y = - 20• 1/2.√3
F2y = - 10√3 N

# F3 = 20 N
Dng arah, θ = 30° Terhadap sumbu Y negatif
F3x = F3.sin θ
F3x = 20• sin 30°
F3x = 20• 1/2
F3x = 10 N
Dan
F3y = - F3.cos θ
F3y = - 20• cos 30°
F3y = - 20• 1/2.√3
F3y = - 10√3 N

Step 1
---------
Fx = F1x + F2x + F3x
Fx = 20 + (- 10) + 10
Fx = 20 N

Step 2
---------
Fy = F1y + F2y + F3y
Fy = 20√3 + (- 10√3) + (- 10√3)
Fy = 0

Step 3
---------
FR = √(Fx² + Fy²)
FR = √(20² + 0²)
FR = 20 N

Step 4
---------
Dng arah,
Tan θ = Fy/Fx
Tan θ = 0/20
Tan θ = 0
θ = 0°

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FZA