tolong banget ya kak bang, besok mau dikumpul... beserta jalannya yaaa

Dik : luas ∆ABD = 48cm2
BD = 8 cm
Jb.
a. Panjang AD =
a x t /2 = 48cm2
BD x AD = (48x2)cm2
8 x AD = 96cm2
AD = 96/8
AD = 12 cm

b. Panjang CD =
Pakai perbandingan :
∆ABD : ∆ACD
BD/AD = AD/CD
8/12=12/CD
8CD = 12x12
8CD = 144
CD = 144/8
CD = 18 cm