Matematika

Pertanyaan

integral dari 1 sampai 2×^2 - 3×+2 dx

1 Jawaban

  • InTegraL

    ∫(x² - 3x + 2) dx [2...1]
    = x³/3 - 3x²/2 + 2x
    = (2³/3 - 3.2²/2 + 2.2) - (1/3 - 3/2 + 2)
    = (8/3 - 6 + 4) - (1/3 + 1/2)
    = 2/3 - 5/6
    = (4 - 5)/6
    = -1/6

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