Fungsi f dinyatakan dengan rumus f(x)=ax+b, jika f(x)=ax+b, jika f(2)=3 dan f(-3), nilai a+b adalag

f(x)=ax+b
f(2)=2a+b = 3
f(-3)=-3a+b = 0 -
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5a=3
a=3/5

2a+b = 3
2.3/5+ b = 3
6/5 + b = 3
b = 3 -6/5
b= 9/5

a+b = 3/5+ 9/5 = 12/5 = 2 2/5