jika log 2=a log 3=b maka 9 log24=

9'log24

3^2'log2^3 * 3
3^2'log2^3 + 3^2'log3

3/2* 3'log2 + 1/2* 3'log3
3/2* (log2/log3) + 1/2 * 1
(3/2) (a/b) +1/2
3a/2b + 1/2

Kalau bingung baca jawaban ku.. Baca baca sifat sifat log di buku

log 2=a log 3=b

=> 9 log24
= (log 24) / (log 9)
= (log 2×2×2×3) / (log 3×2)
= (3× log 2) + log 3 / ( log 3 +log 2)
= [(3× a ) +b] / (b+a)
= ( 3a+b) /( b+a)