Nilai dari 2log48+2logakar1bagi6-2log3= tolong di jawab sekarang yaaa

Nulis soal nya gini aja dah

2'log48 + 2'log (1/sqrt(6)) - 2'log3
2'log(2^4*3) + 2'log (1/[(2)^(1/2) (3)^(1/2)] - 2'log3

2'log2^4 + 2'log3 + 2'log(2)^(-1/2) + 2'log(3)^(-1/2) - 2'log3

4 (1) - 1/2 (1) - 1/2* 2'log3
3,5 - 0,5 * 2'log3

Panjang uyy

Vh
2log48+2logakar1bagi6-2log3=
2log ( 48 x√ 1/6) : 3)
2log ( 48/3 x√ 1/6)
2log ( 16 x√ 1/6)
2log (2⁴×√ 1/6)
2log 2⁴+ 2log√ 1/6
4 + 2log√ 1/6