Cari substitusi dan eliminasiX+2y+z=0,-x+y+z=-4,2x+3y+z=1

x + 2y + z = 0
x + y + z = -4
2x + 3y + z = 1

x + 2y + z = 0
x + y + z = -4
------------------- -
y = -4

x + 2y + z = 0
2x + 3y + z = 1
-------------------- -
-x + -y = -1

-x + -y = -1
y = -4
--------------- +
-x = -5
x = 5

x + 2y + z = 0
5 + 2 (-4) + z = 0
5 + (-8) + z = 0
-3 + z = 0
z = 3