sin150derajat x sin 15 derajat adalah
Matematika
renu7
Pertanyaan
sin150derajat x sin 15 derajat adalah
2 Jawaban
-
1. Jawaban dylancp
Sin150°·Sin15°
= 1/2(cos135°-cos165°)
= 1/2(√2/2-cos165°)
= √2/4-cos165° -
2. Jawaban RanshiVM
sin150° = sin(30° + 120°)
sin(30° + 120°) = sin30° . cos120° + cos30° . sin120°
= 1/2 . -1/2 + (1/2)√3 . (1/2)√3
= -1/4 + 3/4
= 1/2
sin15° = sin(45° - 30°)
sin(45° - 30°) = sin45° . cos 30° - cos45° . sin30°
= (1/2)√2 . (1/2)√3 - (1/2)√2 . 1/2
= (1/4)√6 - (1/4)√2
= (√6 - √2)/4
sin150° . sin15° = 1/2 . (√6 - √2)/4
= (√6 - √2)/8
Silakan dicek kembali. Semoga membantu.