Matematika

Pertanyaan

Tentukan nilai x yang memenuhi persamaan 2log2logx=2log(10-2logx2)+1

1 Jawaban

  • ²Log (²Log x) = ²Log (10-²Log x²)+ 1
                           = ²Log (10-²Log x²)+ ²Log 2
                           = ²Log (10-²Log x²)(2)
                           = ²Log (20- 2 ²Log x²)
      coret ²Log       

            ²Log x   = 20 - 2 ²Log x²
                          = 20 - ²Log x⁴
                         = ²Log 2²⁰ - ²Log x⁴
                         = ² Log 2²⁰/x⁴
     
      coret ²Log
     
                   x = 2²⁰ / x⁴
                   x⁵ = 2²⁰
                       = (2⁴)⁵
                       = 16⁵
     
      coret pangkat 5
     
                   x = 16

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