bantu jawab ya pliss

[tex]\int_{-1}^{3} (6x+c) dx = [\frac{6}{1+1}x^{1+1}+cx]_{-1}^{3} \\ \int_{-1}^{3} (6x+c) dx = [3x^{2}+cx]_{-1}^{3} \\ \int_{-1}^{3} (6x+c) dx = [27+3c] - [3-c] \\ 26 = [27+3c] - [3-c] \\ 26 = 24+4c \\ 2 = 4c \\ \frac{1}{2} = c[/tex]