Jika x = 27, y = 16, tentukan ∛x2= ∜y3=

1) akar 3 dari x2=(x2)^(1/3)
=(27x2)^(1/3)
=[(3^3)x2)^(1/3)
=(3^3)^(1/3) x 2^(1/3)
=3x akar 3 dari 2
2) akar 4 dari y3=(y3)^(1/4)
=(16x3)^(1/4)
=(16)^(1/4)x(3)^(1/4)
=(2^4)^(1/4)x(3)^(1/4)
=2 x akar 4 dari 3