Berapakah nilai dari: a. 3log (243/27) b. Jika diketahui log 2 = 0,301, log 3 = 0,477, maka nilai log 6 adalah

a) 3log(243/27)=3log(9)
=2
b) log6=log(2x3)
=log2+log3
=0,301+0,477
=0,778

a)
3log (243/27)
= 3log (3^5/3^3)
= 3log 3^2
= 2

b)
log 2 = 0,301
log 3 = 0,477
log 6 = ...?

log 6 = log (2 x 3)
= log 2 + log 3
= 0,301 + 0,477
= 0,778