diket f(x)=ax+b,dan f(4)=5,f(2)=-7
Matematika
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Pertanyaan
diket f(x)=ax+b,dan f(4)=5,f(2)=-7
1 Jawaban
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1. Jawaban intansarii3
F(x) = ax + b
F(4) = 4a + b = 5
F(2) = 2a + b = -7
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2a = 12 => a = 12/2 = 6
2a+b = -7
2.6 + b = -7
12+b = -7 , pindah ruas
b = -7-12 => b = -19
Rumus F(x) = 6x - 19
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