Tolong ya no1 pakai cara terima kasih

a. Fa = 8 N, xa = 5 cm = 0.05 m
Fb = 12 N, xb = 6 cm = 0.06 m
konstanta pegasnya
k = Fa/xa = 8/0.05 = 160 N/m

b. energi potensial dititik B
E.p = ½k (xb)²
E.p = ½(160) (0.06)²
E.p = 0.288 joule