Log 3=0,477 ,Log 5=0,6990 maka log 45 ?

[tex]\log {45} = \log{(3\times3\times5)} \\ \log {45} = \log{3}+\log{3}+\log{5} \\ \log{45} = 2(\log{3}) + \log{5} \\ \log{45} = 2(0,477)+(0,699) \\ \log{45} = 0,954 + 0,699 \\ \log{45} = 1,644[/tex]