r alas kerucut = 21cm luas selimut = 2310cm^2 v = ?
Matematika
mkhairul2202
Pertanyaan
r alas kerucut = 21cm
luas selimut = 2310cm^2
v = ?
luas selimut = 2310cm^2
v = ?
1 Jawaban
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1. Jawaban tetimala
π x r x s = luas selimut
22/7 x 21 x s = 2310
66 x s = 2310
s = 2310 : 66
s = 35
mencari tinggi
t = √35²-21²
t = √1225-441
t = √784
t = 28
volume = 1/3 x π x r² x t
1/3 x 22/7 x 21 x 21 x 28
22 x 21 x 28 = 12936 cm³
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