Jika ²log a + ²log b=12 dan 3 ²log a - ²loga b =4 maka a+b? (Tolongdikasih caranya) (Makasih bgt)

²log a + ²log b = 12
²log ab = 12
ab = 2^12
²log a - ²log b = 4
²log a/b = 4
a/b = 2⁴
a = b(2⁴)

ab = 2^12
{b(2⁴)}b = 2^12
b² = 2^12 / 2⁴
b² = 2^(12-4)
b² = 2^8
b = 2⁴ = 16
a = b(2⁴)
a = (2⁴)(2⁴)
a = 2^8 = 256
a + b = 256 + 16 = 272

^ tanda pangkat