tentukanlah nilai n pada pertanyaan diatas

n>0

0 Int n(2x+2) dx = 12
[ x² + 2x ]n 0 = 12
(n²+2n) - (0²+2(0)) = 12
n² + 2n = 12
n² + 2n - 12 = 0

x1,2 = -2 +/- √2²-4(1)(-12) /2(1)
= -2 +/- √52 / 2
= -2 +/- 2√13 /2
= -1 +/- √13
√13 = 3,6
x1= -1 + 3,6 = 2,6 mendekati 3

x2 = -1 - 3,6 (TM)


=> E